y^2+y-22650=0

Solution for y^2+y-22650=0 equation:

y^2+y-22650=0

a = 1; b = 1; c = -22650;
Δ = b2-4ac
Δ = 12-4·1·(-22650)
Δ = 90601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{90601}=301$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-301}{2*1}=\frac{-302}{2}
=-151
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+301}{2*1}=\frac{300}{2}
=150
$